Question

A milkman has 14 litres of one type of milk and 18 litres of other type. Find the least number of equal sized containers required to store all the milk without mixing​

Answer 1

Given,

Quantity of first type of milk = 14 litres

Quantity of second type of milk = 18 litres

To find,

The least number of equal sized containers required to store all the milk without mixing.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

First of all, we have to calculate the capacity of one of the equal sized containers, that we will use in this case. For that, we need to calculate the HCF of the given milk quantities.

Capacity of equal sized containers :

14 = 2×7

18 = 2×3×3

Common factor = 2

So, HCF = 2

Which implies, capacity of equal sized containers = 2 litres

Total containers required to store first type of milk = (14÷2) = 7

Total containers required to store second type of milk = (18÷2) = 9

Total containers required to store all the milk = (7+9) = 16

Hence, we need a minimum of 16 containers (each of 2 litres capacity) to store all the milk without mixing.