A milkman has 150 L of milk of higher fat and 240 L of milk off lower fat. you want to pick the milk in this of equal capacity. what should be the capacity of each tin?
Answers
Answered by
12
Hello,
Milkman is having milk and we need to find the capacity of each tin which can be used to pick the milk with equal capacity.
This question is not directly asking what we have to do. But we have to find the HCF.
The capacity of the milk with :-
Higher fat - 150 l
Lower fat - 240 l
So, HCF (150,240) by prime Factorization....
150- 2*3*5*5
240- 2*2*2*2*5*3
Hcf is equal to 2*3*5 = 30 l
So, the capacity of the tin should be equal to 30 l
Milkman is having milk and we need to find the capacity of each tin which can be used to pick the milk with equal capacity.
This question is not directly asking what we have to do. But we have to find the HCF.
The capacity of the milk with :-
Higher fat - 150 l
Lower fat - 240 l
So, HCF (150,240) by prime Factorization....
150- 2*3*5*5
240- 2*2*2*2*5*3
Hcf is equal to 2*3*5 = 30 l
So, the capacity of the tin should be equal to 30 l
Answered by
2
Answer:
30 liters
Step-by-step explanation:
Hello,
Milkman is having milk and we need to find the capacity of each tin which can be used to pick the milk with equal capacity.
This question is not directly asking what we have to do. But we have to find the HCF.
The capacity of the milk with :-
Higher fat - 150 l
Lower fat - 240 l
So, HCF (150,240) by prime Factorization....
150- 2*3*5*5
240- 2*2*2*2*5*3
Hcf is equal to 2*3*5 = 30 l
So, the capacity of the tin should be equal to 30 l
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