Question

A milkman has 2 cans the first can contains 33.33% water and wine the second 25% water and the rest is wine how much wine should he mix from each of the container so as get 14 litres of wine such that the ratio of water and wine is 2 isto5

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Answer 1

($\frac{33.33}{100}$) * x + ($\frac{25}{100}$) * y = 4.

Solving the equation will give us the values of x and y, which represent the amounts of wine to be mixed from each can to obtain 14 liters of wine with a water-to-wine ratio of 2:5.

Explanation:

Let's assume that the milkman needs to mix x liters of wine from the first can and y liters of wine from the second can to get a total of 14 liters of wine.

From the first can:

The percentage of wine in the first can is 100% - 33.33% = 66.67%.

So, the amount of wine in the first can is ($\frac{66.67}{100}$) * x liters.

From the second can:

The percentage of wine in the second can is 100% - 25% = 75%.

So, the amount of wine in the second can is ($\frac{75}{100}$) * y liters.

According to the given ratio, the amount of water in the mixture should be ($\frac{2}{7}$) * 14 liters = 4 liters.

Since water is not added separately, the total amount of water in the mixture will be the sum of the water present in the two cans.

From the first can:

The amount of water in the first can is ($\frac{33.33}{100}$) * x liters.

From the second can:

The amount of water in the second can is ($\frac{25}{100}$) * y liters.

Setting up the equation:

($\frac{33.33}{100}$) * x + ($\frac{25}{100}$) * y = 4.

Now, we need to find the values of x and y that satisfy this equation. This can be done through various methods like substitution, elimination, or graphical representation.

Solving the equation will give us the values of x and y, which represent the amounts of wine to be mixed from each can to obtain 14 liters of wine with a water-to-wine ratio of 2:5.

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