A Milkman has 20 liter he sold 153/5 of milk
how much milk he left over
Answers
Answer:
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Step-by-step explanation:
Given:
A milkman has 20 Litres of milk
He sells 15 3/5 Litres of milk
To find:
The quantity of milk is left to be sold
Solution:
The quantity of the milk sold by the milkman = 15\frac{3}{5}\:L = \frac{78}{5}\:L15
5
3
L=
5
78
L
The total quantity of milk that the milkman has = 20 L
Therefore,
The quantity of milk left after selling is,
= [Total quantity of milk] - [Quantity of milk sold]
= 20 - \frac{78}{5}20−
5
78
= \frac{100\:-\:78}{5}
5
100−78
= \frac{22}{5}
5
22
= \bold{4.4\:L}4.4L
Thus, 4.4 Litres of milk is left to be sold.
Answer:
Original 20 litre water added is 5 litre.Percentage of water is equal to5/20*100=25 percent
Cost price of milk= selling price. Profit = percent of water in mix = 25 percent.
Or alternatively COST PRICE OF 20 LT MILK= 20*18= RS. 360
SELLING PRICE OF MIX( 20 LTMILK+5 LT.WATER=25 LT.)= 25*18=RS.450
Profit= SP- CP=450–360=RS.90
Profit percent= 90/360*100= 25
Step-by-step explanation:
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