a milkman has containers having capacity of 180 and 162 litres of milk what is the capacity of large container that can be used to fill the container completely
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Answered by
42
the capacity of the larger contianer = sum of small container=342
Answered by
85
we need to ding HCF(180,162)
180=2×2×3×3×5
162=2×3×3
HCF(180,162)=2×3×3=18
required container is of 18 liter
180=2×2×3×3×5
162=2×3×3
HCF(180,162)=2×3×3=18
required container is of 18 liter
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