Question

A milkman has two types of milk. In the first container the percentage of milk is 80% and in the second container the percentage of milk is 60%. If he mixes 28 litres of milk of the first container to the 32 litres of milk of the second container, then the percentage of milk in the mixture is:

63.99
69.33
72.5
75.2​

Answer 1

Answer:

72.5 will be the correct answer

Answer 2

Answer:

69.33%

Step-by-step explanation:

Concept= Quantitative Aptitude

Given= Two Milk % and Mixture volume

To Find= Milk% in Mixture

Explanation=

We have been given that,

A milkman has two types of milk. In the first container the percentage of milk is 80% and in the second container the percentage of milk is 60%. If he mixes 28 litres of milk of the first container to the 32 litres of milk of the second container.

total volume of mixture will be 28+32=60litres

From First mixture the milkman takes 28litres in which milk is 80%

So, milk taken from first= 80%of 28= 0.8*28=22.4litres

From second mixture the milkman takes 32lites in which milk is 60%

So, milk taken from second= 60% of 32= 0.6*32=19.2litres

Volume of Milk in mixture is 22.4+19.2=41.6litres

% of milk in mixture= 41.6/60 *100= 0.69333*100=69.33%.

Therefore the percentage of milk in mixture is 69.33%.

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