Question

A milkman has two types of the milk.in the first container the percentage of milk is 80%.while in the second it is 60%.if he mices 29 liters of milk of the first container with 32 litres of milk of the second container, then the percentage of milk in the mixture is?

Answer 1

69.67%
$69.67\%$

Answer 2

Answer:

69.51 % ( approx )

Step-by-step explanation:

Since, 29 liter of milk solution having 80 % of milk is mixed with the 32 liters of milk having 60 % of milk,

Thus, the total quantity of mixture = 29 + 32 = 61 liters,

Also, The milk in resultant solution = The quantity of milk in 80 % of milk solution +  The quantity of milk in 60 % of milk solution

= 80 % of 29 + 60% of 32

$=\frac{80\times 29}{100}+\frac{60\times 32}{100}$

$=\frac{2320}{100}+\frac{1920}{100}$

$=\frac{4240}{100}=42.40\text{ liters}$

Thus, the percentage of milk in resultant milk solution = $\frac{42.40}{61}\times 100$

$=\frac{4240}{61}=69.5081967\approx 69.51\%$