Math, asked by hiteshsahu094, 5 hours ago

a milkman sell 2 cows of 20,000 .his one cow sell profit 5% and second cow sell 10%loss .total rupees loss and profit

Answers

Answered by MoMcALLinG
0

Step-by-step explanation:

Cost price of 1st cow.

=20,000×100÷105

=Rs.1907.61

Cost price of 2nd cow

=20,000×100÷90

=22222.22

Total C.P=19047.61+22222.22

=Rs.41269.84

Total S.P=Rs.40,000

Overall loss =C.P−S.P

=Rs.41,269.84−Rs.40,000

=Rs.1269.84

Therefore, the milkman has a loss of Rs.1269.84.

Answered by lokeshmehra309
0

Step - by - step explanation : Cost price of 1st cow. = 20,000 × 100-105 = Rs.1907.61 Cost price of 2nd cow = 20,000 × 100 90 = 22222.22 Total CP = 19047.61 + 22222.22 = Rs.41269.84 Total SP = Rs.40,000 Overall loss = CP - SP = Rs.41.269. 84 - Rs.40.000 = Rs.1269.84 Therefore, the milkman has a loss of Rs. 1269.84.

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