A milkman sold two of his buffaloes for 20,000 each. one he made a gain of 5% and on the other a loss of 10%. Find his overall gain loss. (Hint: find CP of each)
Answers
Sp of buffalo1 = Rs 20,000
Gain =5%
So, Cost price of buffalo1 = 100/90 ×20,000= Rs. 19047.62
SP of buffalo2 = Rs 20,000
Loss =10%
Cost price of buffalo2 = 100/90 ×20,000= Rs 22,222.22
Total Cost price = Rs 41269.84
Total selling price = Rs 40,000
Loss = Rs 1269.84
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Answer:
Solution:
S.P. of each buffalo = Rs.20,000
S.P. of two buffaloes = 20000 x 2
= Rs. 40,000
One buffalo is sold at 5% gain.
Let C.P. be Rs.100, then S.P. = 100 + 5
= Rs.105
\because When S.P. is Rs.105, then C.P. = Rs.100
\therefore When S.P. is Rs.1, then C.P. = \frac{100}{105}
\therefore When S.P. is Rs.20,000, then C.P.
= \frac{100}{105}\times20000=Rs.\ 19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be Rs.100, then S.P. = 100 – 10
= Rs.90
\because When S.P. is Rs.90, then C.P. = Rs.100
\therefore When S.P. is Rs.1, then C.P. = \frac{100}{90}
\therefore When S.P. is Rs.20,000, then C.P.
= \frac{100}{90}\times20000=Rs.\ 22,222.22
Total C.P. = Rs.19,047.62 + Rs.22,222.22
= Rs.41,269.84
Since C.P. >S.P.
Therefore here it is a loss.
Loss = C.P. – S.P.
= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84