a milkman sold two of his buffaloes for 20000 each .on one he made a gain of 5 percent and on the other a loss of 10 percent .find his overall gain and loss.(HINT:find the cp of each )
Answers
Answered by
4
Step-by-step explanation:
Step-by-step explanation:
First buffalo ......
SP = rs20000
( let CP be x )
Gain =5% of CP
= 5/100 × X = X/ 10
SP= CP+GAIN = x +x/20 = 21x/20
20000= 21x/20
x = 20 × 20000/ 21
= 19047.62
Second buffalo......
SP = rs20000. ( let CP be y )
Loss= 10% of CP
= 10/ 100× y
= y/10
SP= CP - LOSS ( y - y/10 = 9/10y )
20000= 9/10y
or, y = 10× 20000/9
= 22222.22
total SP= rs (20000+20000) = rs40000
total CP= rs ( 19047.62 + 22222.22 ) = rs41269.84
CP > SP
therefore, loss = ( 41269.84 - 40000 ) = rs 1269.84 ANS
Hope it helps you
Similar questions