a milkman sold two of his buffaloes for 20000 each.on one he made a gain of 5% and on the other a loss of 10% find his overall gain or loss (hint:find cp of each)
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1
2000×5/100 =1000 and then 2pqr equals x by supplementary angle theoram 6x6ź equals to 100
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C.P = [( 100 /100 + Gain % )× S.P ]
C.P =[ 100 /105 ]× 20000
C.P = 19047.619.....
GAIN = S.P - CP
= 20000 - 19047.619
= 952.38.......
THE C.P WILL BE SAME FOR BOTH BUFFALOES ,
IN SECOND BUFFALO ,
LOSS = 10 %
LOSS = TWICE OF GAIN IN FIRST BUFFALO [ BECAUSE THE GAIN IS 5 % AND LOSS IS 10 % , SO IT IS ]
= 2 × 952.38
= 1904.76........
LOSS IN SECOND BUFFALO > GAIN IN FIRST BUFFALO
LOSS = 1904.76 - 952.38
= 952.38.......ANS....
C.P =[ 100 /105 ]× 20000
C.P = 19047.619.....
GAIN = S.P - CP
= 20000 - 19047.619
= 952.38.......
THE C.P WILL BE SAME FOR BOTH BUFFALOES ,
IN SECOND BUFFALO ,
LOSS = 10 %
LOSS = TWICE OF GAIN IN FIRST BUFFALO [ BECAUSE THE GAIN IS 5 % AND LOSS IS 10 % , SO IT IS ]
= 2 × 952.38
= 1904.76........
LOSS IN SECOND BUFFALO > GAIN IN FIRST BUFFALO
LOSS = 1904.76 - 952.38
= 952.38.......ANS....
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