A milkman sold two of his buffaloes for Rs. 18,000 each.
On one he made a gain of 5% and on the other a loss of
10%. Find his overall gain or loss. (Hint: Find
CP of each)
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buffalo = Rs 20000 The milkman made a gain of 5% while selling one buffalo. This means if C.P. is Rs 100, then S.P. is Rs 105. C.P. of one buffalo =2000×100/105= Rs 19,047.62 Also, the second buffalo was sold at a loss of 10%. This means if C.P. is Rs 100, then S.P. is Rs 90. ∴C.P. of other buffalo =2000×100/90= Rs 22222.22 Total C.P. = Rs 19047.62 + Rs 22222.22 = Rs 41269.84 Total S.P. = Rs 20000 + Rs 20000 = Rs 40000 Loss = Rs 41269.84 − Rs 40000 = Rs1269.84 Ans,- ,the loss of milkman is, Rs 1,269.84.
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Solution :
A milkman sold two of his buffaloes for Rs.18000 each. On one he made a gain of 5% & on the other a loss of 10% .
Using formula of the cost price as given gain % :
- A milkman sold one buffalo = Rs.18000
- On his buffalo gain = 5%
- Cost price on first buffalo = ?
A/q
Using formula of the cost price as given loss % :
- A milkman sold other buffalo = Rs.18000
- On his buffalo loss = 10%
- Cost price of other buffalo= ?
Total cost price of both buffalo = Rs.17142.85 + Rs.20000 = Rs.37142.85
Total selling price of both buffalo = Rs.18000 + Rs.18000 = Rs.36000
C.P > S.P
⇒ Loss = Cost price - Selling price
⇒ Loss = Rs.37142.85 - 36000
⇒ Loss = Rs.1142.85
Now;
Thus;
The overall his loss% will be 3.07 % .
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