a milkman sold two of his buffaloes for Rs 20000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss.(hint: find the CP of each).
Answers
Hey mate ,
See the attachment.
Answer:
Let cost price of 1st buffalo=₹x
Given,gain percent on 1st buffalo=5%
Gain percent on 1st buffalo=5% of cost price of 1st buffalo5% of ₹
=₹(5/100×x)
=₹5x/100
selling price of 1st buffalo= cost price of 1st buffalo + Gain amount on 1st buffalo
=₹(x+5x/100)
=₹(100x+5x/100)
=₹105x/100
But selling price of 1st buffalo=₹20000
105x/100=20000
=⟩105x=20000×100
=⟩x=20000×100/105
=⟩x=400000/21
=x=₹19047.62
Let cost price of 2nd buffalo be ₹y.
Given loss percent of 2nd buffalo=10% of cost price of 2nd buffalo
=10% of ₹y
=₹(10/100×y)
=₹10y/100
selling price of 2nd buffalo=cost price of 2nd buffalo-loss amount on the buffalo
=₹(y-10y/100)
=₹(y-10y/100)
=₹(100y-10y/100)
=₹90y/100
But selling price of 2nd buffalo=₹20000
=90y/100=20000
=⟩90y=20000×100
=⟩y=20000×100/90
=⟩y=20000/9
=⟩y=₹22222.22
Total cost price of both buffalo=₹(x+y)
=₹19047.62+₹22222.22
=₹41269.84
Total selling price of both buffalo=₹20000+₹20000
=₹40000
SP<CP
loss amount on both buffaloes
cost price of both buffaloes-selling price of both buffaloes=₹41269.84-₹40000
=₹1269.84
Hence, overall loss is ₹1269.84