Question

A milkman sold two of his buffaloes for Rs 20000 each.On one he made a gain of 5% and on the other a loss of 10%.Find his overall gain or loss.(Find CP of each).

Answer 1

buffalo = Rs 20000 The milkman made a gain of 5% while selling one buffalo. This means if C.P. is Rs 100, then S.P. is Rs 105. C.P. of one buffalo =2000×100/105= Rs 19,047.62 Also, the second buffalo was sold at a loss of 10%. This means if C.P. is Rs 100, then S.P. is Rs 90. ∴C.P. of other buffalo =2000×100/90= Rs 22222.22 Total C.P. = Rs 19047.62 + Rs 22222.22 = Rs 41269.84 Total S.P. = Rs 20000 + Rs 20000 = Rs 40000 Loss = Rs 41269.84 − Rs 40000 = Rs1269.84 Ans,- ,the loss of milkman is, Rs 1,269.84.

Answer 2

Step-by-step explanation:

First buffalo ......

SP = rs20000

( let CP be x )

Gain =5% of CP

= 5/100 × X = X/ 10

SP= CP+GAIN = x +x/20 = 21x/20

20000= 21x/20

x = 20 × 20000/ 21

= 19047.62

Second buffalo......

SP = rs20000. ( let CP be y )

Loss= 10% of CP

= 10/ 100× y

= y/10

SP= CP - LOSS ( y - y/10 = 9/10y )

20000= 9/10y

or, y = 10× 20000/9

= 22222.22

total SP= rs (20000+20000) = rs40000

total CP= rs ( 19047.62 + 22222.22 ) = rs41269.84

CP > SP

therefore, loss = ( 41269.84 - 40000 ) = rs 1269.84 ANS