Question

a milkman uses a container in the shape of a frustum of a cone to store milk the container open from the top is of height 40cm with radii of its lower and upper circular ends as 14 cm and 35cm respectively find the volume of the milk in litres which can completely filled the container .if he sells the milk at rupees 35 per litre how much amount he can sell the whole milk

Answer 1

h=40cm
r1=35cm
r2=14cm

Volume of the container
= 1/3πh(r1²+r2²+r1r2)
1/3π ×16(1225+196+490)
1/3 π ×16(1911)
π ×16×637
22/7 × 16×637
=32032 cm³
= 32.032cm³
Cost of milk = Rs. 1121.12


Hope it helps.......

Answer 2

Thank you for asking this question. Here is your answer:

We will use the following formula to solve this question:

1/3πh(r1²+r2²+r1r2)

and we will put the following values into it:

h = 40 cm

r1 = 35 cm

r2 = 14 cm

1/3π ×16(1225+196+490)

1/3 π ×16(1911)

π ×16×637

22/7 × 16×637

= 32032 cm³

So the final answer is 32032 cm³

If there is any confusion please leave a comment below.