a milkman uses a container in the shape of a frustum of a cone to store milk the container open from the top is of height 40cm with radii of its lower and upper circular ends as 14 cm and 35cm respectively find the volume of the milk in litres which can completely filled the container .if he sells the milk at rupees 35 per litre how much amount he can sell the whole milk
Answers
Answered by
12
h=40cm
r1=35cm
r2=14cm
Volume of the container
= 1/3πh(r1²+r2²+r1r2)
1/3π ×16(1225+196+490)
1/3 π ×16(1911)
π ×16×637
22/7 × 16×637
=32032 cm³
= 32.032cm³
Cost of milk = Rs. 1121.12
Hope it helps.......
r1=35cm
r2=14cm
Volume of the container
= 1/3πh(r1²+r2²+r1r2)
1/3π ×16(1225+196+490)
1/3 π ×16(1911)
π ×16×637
22/7 × 16×637
=32032 cm³
= 32.032cm³
Cost of milk = Rs. 1121.12
Hope it helps.......
sindhug1612:
height is 40 right
you are totaly wrong
because in question it is given that top of frustum is open
so we have to substract the circle for ir
Your answer is wrong
H=40 not 1*
Not 16
You could have 7^2 common instead of calculation square of 35, 14 and value of 35x14
i am getting i am getting 80.08 litres
is it correct
Answered by
6
Thank you for asking this question. Here is your answer:
We will use the following formula to solve this question:
1/3πh(r1²+r2²+r1r2)
and we will put the following values into it:
h = 40 cm
r1 = 35 cm
r2 = 14 cm
1/3π ×16(1225+196+490)
1/3 π ×16(1911)
π ×16×637
22/7 × 16×637
= 32032 cm³
So the final answer is 32032 cm³
If there is any confusion please leave a comment below.
where did 16 come from
hieght is 40cm
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