Question

A minaris a tower or a turret found especially in India it is the famous monument of tourist attractions including the other places near a tourist from all over the world come here every year to see the beauty of the historical monuments one day a 1.5 metres tall boy when For a excursion trip he saw beautiful Minar and he asked bout the height of the mirror from the local guide the local guide told him that the height of the Minar is 30 approximately he is standing at some distance from the Minar and observes the angle of elevation from his eyes the top of the building increases from alpha to the beta he walks towards it such that sin alpha + beta equal to 1 and Cos theta minus Alpha equal to root 3 by 2 find the distance he walked towards the building ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given : A Minar of height 30 m , boy 1. 5 m , Angle of elevation α & β , Sin(α+β) = 1  Cos(β - α) = √3 / 2

To find : Distance covered by boy

Solution:

Height of Minar above boy = 30 - 1.5 = 28 m

Sin( α + β) =  1

=>  α + β = 90°

Cos( β - α) =  √3 /2

=>  β - α = 30°

Adding both 2 β = 120°

=>  β = 60°

& α = 30°

Tan 30°  =  28.5/ (initial Horizontal Distance )

=> initial Horizontal Distance  = 28.5√3

Tan 60°  =  28.5/ (Final Horizontal Distance )

=> Final Horizontal Distance  = 28.5/√3

Distance covered =  28.5√3 - 28.5/√3

= (28.5 * 3 - 28.5)/√3

= 57/√3

= 19√3  m

= 32.9 m

the distance he walked towards the building ​ =  19√3  m = 32.9 m

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