a mineral water sample was analysed and found to contain 1×10^-3 ammonia(W%W).Then what will be the mole of ammonia gas present in 1L water
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Answer; 5.8X10(power 10^-4) mole
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Answer:
percentage of ammonia (%W/W)= 10^-3
1 litre water = 1000 ml
density of water = 1 gm/ml
D= M/V
M = D*V
M=1 gm/ml *1000 ml
M = 1000gm
mass of ammonia = (10^-3/ 100)* 1000
mass of ammonia = 10^-2
molecular mass of ammonia = 17
moles of ammonia = mass / molecular mass
moles of ammonia = (10^-2)/ 17
moles of ammonia = 5.8 *10^-4
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