Question

A mini bus starts from the position of rest at a bus stop with uniform acceleration. During the 10th minute of its motion it covers a distance of 950 m. Calculate its acceleration and the total distance covered in 10 minutes.

Answer 1

Answer:

Explanation:

here given u=0 t=10m s10-s9=95m

s10=ut+1/2at2

s10=0+1/2×a×100=50a

s9=ut+1/2at2

s9=0+1/2×a×81=81/2a

s10-s9=50a-40.5a

95m =9.5a

a=10m/minute squre...

so..acceleration is 10m/minute square....if you convert it intom/s2 then we get 10/3600s2=0.00277m/s2

s=0+1/2at2

s=1/2×10×100=500m