Math, asked by wicliffetom, 3 months ago

A minibus had 23 passengers at the beginning of a journey.twelve passengers alighted at the first stop while 9 boarded .Six of those who boarded at the first stop alighted at the second stop and 12 got in.the minibus did not stop again up to the final destination.the charges from the starting point were sh 50 up to the first stop,sh 70 up to the second stop and sh 85 up to the final destination.how much money was collected during the trip?

Answers

Answered by Papun99
8

Answer:

Rs. 1940

Step-by-step explanation:

No. of passengers =27

In 1st stop money collected =>

Money collected from 12 passengers from starting to 1st stop=

12×50 = 600 —(eq. 1)

In2nd stop money collected =>

Money collected from 6 passengers from 1st stop to 2nd stop=

6×(70-50) = 120 —(eq. 2)

In final stop money collected =>

(Money collected from 11 passengers from starting to final point) + (Money collected from 3 passengers from 1st stop to final point) + (Money

collected from 12 passengers from 2nd stop to final point) =

935 + 105 + 180 = 1220 (eq. 3)

Adding eq. (1,2,3)

600+120+1220 = 1940

Thus total money collected is Rs. 1940

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