Question

A minibus starts from the position of rest at a bus stop with uniform acceleration.During the 10th minute of its motion it covers a distance of 95 m . calculate its acceleration and total distance it covers in 10 minutes .

Answer 1

here given u=0 t=10m s10-s9=95m
s10=ut+1/2at2
s10=0+1/2×a×100=50a
s9=ut+1/2at2
s9=0+1/2×a×81=81/2a
s10-s9=50a-40.5a
95m =9.5a
a=10m/minute squre...
so..acceleration is 10m/minute square....if you convert it intom/s2 then we get 10/3600s2=0.00277m/s2
s=0+1/2at2
s=1/2×10×100=500m