Question

A minus b minus C whole cube formula

Answer 1

Answer:(a-b-c)^2=a^2+b^2+c^2-2ab+2bc-2ac

Step-by-step explanation:

Answer 2

Answer:

$a^3 - b^3 - c^3- 3a^2b- 3a^2c+ 3ab^2- 3b^2c+3ac^2- 3bc^2+6abc$

Step-by-step explanation:

∵ we know that,

$( a + b )^3 = a^3 + b^3 + 3ab ( a + b )$,

Here, the given expression,

$( a - b - c )^3$

$( a - b - c )^3 = ( a - (b + c ) )^3$

$= a^3 + (- (b + c ))^3 + 3(a)(- (b + c ))(a - (b + c ))$ ( by using the above formula )

$= a^3 - (b + c )^3 - 3(a) (b + c )(a - (b + c ))$

$=a^3 - ( b^3 + c^3 + 3bc ( b + c) ) - 3a(b+c)(a-(b+c))$

$=a^3 - b^3 - c^3 - 3b^2c - 3bc^2 - (3ab + 3ac)(a-(b+c))$

$=a^3 - b^3 - c^3 - 3b^2c - 3bc^2 - 3a^2b + 3ab(b+c) - 3a^2c+ 3ac(b+c)$

$=a^3 - b^3 - c^3 - 3b^2c - 3bc^2 - 3a^2b + 3ab^2+3abc - 3a^2c+ 3abc+3ac^2$

$=a^3 - b^3 - c^3- 3a^2b- 3a^2c+ 3ab^2- 3b^2c+3ac^2- 3bc^2+6abc$