Question

A mire of length 20m and area of cross section 1.25 into 10 raise minus 4 metre square is subjected to a load of 2.5 kg weight the elongation produced in wire is 1 into 10 raise to minus 4 metre calculate young's modulus of the material

Answer 1

Explanation:

a wire of 20m and area of cross section 1.25

Answer 2

Given,

Length of the wire(L)=20m

Area of cross section=1.25×10^-4

Weight of the load=2.5kg

Elongation produced(l)=10^-4

To Find,

Young's modulus of the material.

Solution,

We have weight of the load=2.5kg

Force, mg=(2.5×10)N

For Young's modulus of the material we have the formula,

Y=(F/A)/(l/L)

  =FL/Al

 Putting all those given values in the equation,

Y=2.5×10×20/1.25×10^-4×10^-4

 =4×10^10N/m²

Hence, the young's modulus of the material is 4×10^10 N/m².