Physics, asked by maaratee02, 11 months ago

a mirror forms an erect image 30cm from the object and twice its height . where the mirror must be suited? what is the radius of curvature ?

Answers

Answered by vishnuBose5
11

Answer:

40

Explanation:

m = 2 ( positive as image is erect)

it is a concave mirror as a convex mirror always forms diminished image.

v/u = 2

v =2 u

1/f = 1/v +1/u ( mirror formula)

v - u = 30 ( given)

u = - 30cm

v = - 60cm

f= uv/ u+v

f = -30× 60/90

f= 20 cm

radius of curvature R=2

R=40cm

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