A mirror forms an image of 15 cm from mirror which is real and inverted. If the object is kept at a distance of 10 cm from the mirror. Find the focal length. Also state the type of mirror.
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Thus a virtual and erect image is formed at 15 cm behind the mirror. Magnification, m = – v / u = 15 / -5 = 3. Thus the image formed is virtual, erect and magnified by a factor of 3. 2. An object, 4 cm in size, is placed at 25 cm in front of a concave mirror of focal length 15 cm.
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