A mirror of length 2x is kept in front of a road as shown in fig. A point object is kept at distance x from the mirror. An observer can see the image till distance 12x from the mirror. What is y in terms of x?
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See the diagram.
A'FC and A'GD are similar triangles.
A'F / FC = A'G / GD
X/X = (X+Y) / 6X
1 = (X+Y) / 6X
6 X = X + Y
Y = 5 X
A'FC and A'GD are similar triangles.
A'F / FC = A'G / GD
X/X = (X+Y) / 6X
1 = (X+Y) / 6X
6 X = X + Y
Y = 5 X
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Answer:
Y = 5x
Explanation:
Given
ABC AND ACD ARE TRIANGLES GIVEN
AB/BC =AC/AD
AB =X
BC=X
AC = X+Y
AD = 12X/2X = 6X
SO
X/X = X+Y/6X
6X = X+Y
6X-X = Y
SO Y=5X .
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