Question

A mirror of length 30 cm and width 20 cm is to beframed with a 2 cm wide frame.find the area of the frame required. Also find the cost of farming at the rateof ₹20 per cm sq​

Answer 1

Answer:

length = 30 cm

breath=20 cm

height= 2 cm

rate = rupees 20

Step-by-step explanation:

first step-

• total surface area= 2 (lb+bh+hl)

= 2(30*20+ 20*2+2*30)

=2(600+40+60)

=2*700

=1,400cm/square

• rate = 20 rupees

cost = rate* area

=20*1400

=28000cm square

Answer 2

Answer:

The area of the frame required is 216 sq.cm. and the cost of framing is Rs.4320

Step-by-step explanation:

Length of mirror = 30 cm

Breadth of mirror = 20 cm

Width of frame = 2 cm

So, Outer length = 30+(2+2)=34 cm

Outer breadth = 20+2+2=24 cm

Area of frame = Outer area - inner area = (34 \times 24)-(30 \times 20)=216 sq.cm.(34×24)−(30×20)=216sq.cm.

Cost of framing 1 sq.m. = rs.20

Cost of framing 216 sq.m. = 216 \times 20 = Rs.4320

Hence the area of the frame required is 216 sq.cm. and the cost of framing is Rs.4320