A mirror of length 30 cm and width 25 cm is to be framed with a 4 cm wide frame. Find the area of the frame required. Also find the cost of framing at the rate of ₹ 25 per cm².
Answers
Answer:
Area of frame required=2(20*2+15*2) cm²
=2(40+30) cm²
=2*70 cm²
=140 cm²
Cost of framing 1 cm²=₹15
Cost of framing 140 cm²=₹15×140
=₹2100
Step-by-step explanation:
i think this is the answer
Answer:
(i) The area of frame required is 504 cm².
(ii) Total cost of framing = Rs 12,600.
Step-by-step explanation:
Given: Length of mirror = 30 cm , width of mirror = 25 cm , frame is 4 cm wide and cost of framing = Rs 25 per cm².
Length of frame = length of mirror + 2(4)
⇒ Length of frame = 30 + 8 = 38 cm
And, breadth of frame = width of mirror + 2(4)
⇒ Breadth of frame = 25 + 8 = 33 cm
⇒ Area of frame = (Total area) - (Area of mirror)
⇒ Area of frame = (38 × 33) - (30 × 25)
⇒ Area of frame = 1254 - 750
⇒ Area of frame = 504 cm²
Also, total cost of framing = 25 × (area of frame)
⇒ Total cost of framing = 25 × 504
⇒ Total cost of framing = Rs 12,600