Question

A missile is launched at an angle of 15° to the horizontal with an initial velocity V• to hit a target 300m away. Calculate V• and the maximum height H

Answer 1

Question :-

A missile is launched at an angle of 15° to the horizontal with an initial velocity V to hit a target 300m away. Calculate V and the maximum height H.

Answer :-

Given -

• Range , R = 300 m

• angle of projection , θ = 15°

To Find -

• Initial velocity = V

• maximum height = H

Process -

As per formula

Range,

R = (V² sin 2θ) / g

=> 300 = V² sin 2(15°) / g

=> 300 = V² sin 30° / 10

=> 3000 = V² × 1/2

=> 6000 = V²

=> V² = 6000

=> V = 77.46 m/s

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And,

Height,

H = (V² sin²θ) / 2g

= ( 6000 × sin²15° ) / ( 2 × 10 )

= 6000 × 0.067 / 20

= 300 × 0.067

= 20.07 m

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Hence, the initial velocity is 77.46 m/s and the maximum height reached is 20.07 m .

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.. Thank You !!

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