A missile of mass 2 kg is fixed from a bazooka of mass 80 kg. given that the muzzle speed of the missile is 40 m/s ,calculate the recoil speed of the gun?
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Answer:
Given,
m (mass of missile) = 2 kg
M (mass of the bazooka) = 60 kg
v (muzzle velocity) = 40 m/s
Let V be the recoil speed of the bazooka.
Initial momentum of the system = 0
Final momentum of the system = mv –MV
(There is a –ve sign because the bazooka and missile move in opposite directions)
Now, according to the law of conservation of momentum:
Final momentum = initial momentum
mv – MV = 0
Thus, V = mv/M
= ( 2 x 40 ) / 80
= 1 m / s.
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