Question

A mixture (10080 Liters contains
conic acid and Water in
the ratio 6.3. To make the ratio 3.2, how much additional
amount of Water is required?​

Answer 1

Answer:

1120 liters

Step-by-step explanation:

given that acid:water = 6:3=2:1

so let acid be 2x and water be x

2x+x=3x=10080

x= 3360 lt

amount of acid = 3360 *2 = 6720

amount of water already present = 3360

new ratio requird =3:2

acid:water = 3:2

6720:p=3:2

p = 4480

new volume of water = 4480

additional amount of water added = new - old

= 4480-3369

= 1120 liters