Question

A mixture consist of 500/11% sand, 400/11% gravel and rest cement. Find the weight of mixture which contains 12.5 kg wt of sand. Also determine the weight of mixture that will contain 4kg wt of cement.​

Answer 1

$\huge \pink{Answer}:-$

$sand \: = \frac{500}{11} \%$

$grave \: = \frac{400}{11} \%$

$cement \: = 100\% = \bold{ ( \frac{500}{11} + \frac{400}{11} )\% = \frac{200}{11} = \frac{200}{11}\% }$

Let the weight of mixture of X

Find the determine the weight of mixture that will contain 1kg of cement. The weight of mixture which contains 12.5kg weight of send

$so, \bold{ \frac{500}{11} \%x = 12.5}$

$\bold{ \frac{500}{1100} x = 12.5}$

$\bold{x = 27.5}$

The weight of mixture which contains 12.5kg weight of send is 27.5 kg.

Determine the weight of mixture that will contain 11 kg weight of cement.

$\bold{ so, \frac{200}{11}\% = 11 }$

$\bold{x = 60.5kg}$

The weight of mixture that will contain 11kg weight cement of 60.5 kg.