Question

A mixture consists of 45% sand, 36% gravel and rest cement. Find the (5) weight of the mixture which contains 22.5 kg of sand. Also determine the weight of mixture that will contain 3.8 kg of cement.

Answer 1

Step-by-step explanation:

Let the mixture be 100%

Quantity of sand in the mixture =

11

500

%

Quantity of gravel in the mixture =

11

400

%

Quantity of Cement in the mixture =100%−

11

500

%−

11

400

%

⇒

11

1100÷500−400

%

⇒

11

200

%

Let xKg of mixture contain 12.5Kg of sand

But 100% of mixture contains

11

500

% of sand

⇒

100%

x

=

11

500

%

12.5

⇒x=

500%

12.5×100%

×11Kg

=2.5×11kg

=27.5Kg

let yKg of mixture contain 4Kg of cement

But 100% of mixture contain

11

200

% discount

⇒

100%

y

=

11

200

%

4

y=22Kg