A mixture consists of 45% sand, 36% gravel and rest cement. Find the
weight of the mixture which contains 22.5 kg of sand. Also determine the
weight of mixture that will contain 3.8 kg of cement
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Answer:
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Answer:
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Step-by-step explanation:
Let the mixture be 100%
Quantity of sand in the mixture =
11
500
%
Quantity of gravel in the mixture =
11
400
%
Quantity of Cement in the mixture =100%−
11
500
%−
11
400
%
⇒
11
1100÷500−400
%
⇒
11
200
%
Let xKg of mixture contain 12.5Kg of sand
But 100% of mixture contains
11
500
% of sand
⇒
100%
x
=
11
500
%
12.5
⇒x=
500%
12.5×100%
×11Kg
=2.5×11kg
=27.5Kg
let yKg of mixture contain 4Kg of cement
But 100% of mixture contain
11
200
% discount
⇒
100%
y
=
11
200
%
4
y=22Kg
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