A mixture consists of only two components A and B In 60 litres of this mixture , the components A and B are present in the Ratio 2:1 . what quantity of component B has to be added to this mixture so that the new ratio is 1:2
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Answered by
73
Quantity of A in the mixture = 60 × 2/3 = 40 liters
Quantity of B in the mixture = 60 × 1/3 = 20 liters
Let the quantity of B added to the mixture be x
40/20 + x = 1/2 or x = 60 liters
Quantity of B in the mixture = 60 × 1/3 = 20 liters
Let the quantity of B added to the mixture be x
40/20 + x = 1/2 or x = 60 liters
anonymousgirl27:
i guess
Answered by
61
Let component A be 2x
Let component B be 1x
2x+1x=60
3x=60
x=20
component A=20×2=40
component B=1×20=20
Let component B added =no
40/20+x=1/2
20+x=80
x=80-20
=60l
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