Math, asked by gdode1818gmailcom, 7 days ago

A mixture contain milk and water in ratio 6:5. When 33 liters of mixture
is replaced by same quantity of water then ratio becomes 3 : 4. find initial
quantity of water.

(a) 64
(b) 84
(C)70
(d) 154
(e) 121

Answers

Answered by mahaksharmasharma014
0

A mixture contain milk and water in ratio 6:5. When 33 liters of mixture

is replaced by same quantity of water then ratio becomes 3 : 4. find initial

quantity of water.

(a) 64

Answered by riyabaghel678
2

Answer:

70 litre

Step-by-step explanation:

A mixture contains milk and water in a ratio of 6:5. When 33 litres of the mixture is replaced by the same quantity of water, the ratio becomes 3:4. What is the initial quantity of the water?

Let the quantity of mixture at the start = 11X+33 litre

Quantity of mixture 33 litre are removed = 11 X

Quantity of milk = 6X

Quantity of water = 5X

So when 33 litre of water is added, the equation will be

6 X : 5X +33 :: 3:4

X= 11

Quantity of mixture at the start

= 11× 11 + 33

= 154 litre

Initial quantity of water = 154 × 5/11

= 70 litre

PS: Initial amount of mixture is taken 11X+33 to keep the calculation simple.11X as it is sum of 6+5 and 33 as this amount of mixture is removed before adding water in the mixture.

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