A mixture containing 0.1 M X- and 0.2 M HX calculate ph
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Answer:
Pkb=4
Pka=14-4=10
pH=pka+log[X^-]÷log[HX]
=10+log(0.1÷0.2)
=10+(log1-log2)
=10+0-log2
=10-log2
Explanation:
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