A mixture containing 100 gm H, and 100 gm 02
is ignited so that water is formed according to the
reaction, 2H2 + O2 + 2H20; How much water
will be formed -
(1) 113 gm
(2) 50 gm
(3) 25 gm
(4) 200 gm
Answers
Answered by
5
Answer:
Moles of H2=100÷2=50..moles of oxygen=100÷32=3.125..the limiting reagent is clearly O2.therefore according to the equation ...1 mole of O2 gives 2 mole of water.so 3.125 moles of O2 gives =2×3.125 moles of H20. Moles of H20=6.25.amount of H20=18×6.25=112.5g
Answered by
0
Answer:
50 gm is the anwser. please mark my answer
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Explanation:
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