Question

A mixture containing 100 gm H2 and 100 gm o2 is ignited so that water is formed
according to the reaction, 2H2 +O2 gives 2H20; How much water will be formed
(A) 113 gm (B) 50 gm (C) 25 gm
D 200 gm​

Answer 1

Answer:

Explanation:

Moles of H2=100÷2=50

Moles of oxygen=100÷32=3.125

The limiting reagent is clearly O2

Therefore according to the equation 1 mole of O2 gives 2 mole of water

Thus 3.125 moles of O2 gives =2×3.125 moles of H20

Moles of H20=6.25.amount of H20=18×6.25=112.5g