Question

a mixture containing 100g of h2 and 100g o2 is ignited so that water is formed according to the reaction

Answer 1

Moles of H2=100÷2=50

Moles of oxygen=100÷32=3.125

The limiting reagent is clearly O2

Therefore according to the equation 1 mole of O2 gives 2 mole of water

Thus 3.125 moles of O2 gives =2×3.125 moles of H20

Moles of H20=6.25.amount of H20=18×6.25=112.5g

Answer 2

Answer: 112.5

Explanation:Moles of H2=100÷2=50

Moles of oxygen=100÷32=3.125

The limiting reagent is clearly O2

Therefore according to the equation 1 mole of O2 gives 2 mole of water

Thus 3.125 moles of O2 gives =2×3.125 moles of H20

Moles of H20=6.25.amount of H20=18×6.25=112.5g

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