Question

A mixture containing milk and water in the ratio 7:6 weighs 65kg. How much water is to be added to this mixture to get a new mixture containing milk and water in the ratio 5:6.


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Answer 1

Answer:

Perfect questions for guys interested in maths..

2. The value of x + x(xx) when x = 2 is:

(a) 10, (b) 16, (c) 18, (d) 36, (e) 64

Solution:

x + x(xx)

Put the value of x = 2 in the above expression we get,

2 + 2(22)

= 2 + 2(2 × 2)

= 2 + 2(4)

= 2 + 8

= 10

Answer: (a)

Answer 2

Answer:

$total mixture= 85 kg,</p><p> let: m = amount of milk </p><p>85 - m = amount of water. </p><p> ratio = 27:7 (milk:water),</p><p>7</p><p>27</p><p> </p><p> = </p><p>(85−m)</p><p>m</p><p> </p><p> </p><p>Solve for m using cross-multiplication: </p><p>27(85−m)=7m</p><p>2295−27m=7m</p><p>2295=34m</p><p>m=135/2</p><p>135/2 kg milk, which means that we have: </p><p>water=85 - 135/2 </p><p> =170/2 - 135/2 </p><p> =35/2 kg water </p><p> water to be added to make the ratio 3:1. </p><p>Let n = amount of water added. </p><p>3/1=(135/2)/(35/2+n)</p><p>Now, solve for n. Again, start with cross multiplication: </p><p>3(35/2+n)=135/2</p><p>105/2+3n=135/2</p><p>3n=30/2</p><p>n=5 [/tex</p><p><strong>Step-by-step explanation:</strong></p><p>[tex] hope it helps you$