A mixture contains 0.05 moles each of CH3COONa and
CH3COOH. Its pH will be (pKa of CH3COOH = 4.74)
4.74
2.26
11.26
7.26
Answers
Answered by
4
Answer:
option (a)
Explanation:
acidic buffer solutions have their ph in between 4-7 .......therefore by elimination we have ......
Answered by
3
Given - Number of moles of salt and acid - 0.05 moles
pKa value of CH3COOH = 4.74
Find - pH of given mixture.
Solution - pH of given mixture is calculated by the Henderson-Hasselbalch equation (pH = pKa + log [A-]/[HA]). In this formula, [A-]/[HA] are concentrations of salt and acid respectively.
Keeping the values in equation-
pH = 4.74 + log (0.05/0.05)
pH = 4.74 + log 1
pH = 4.74 + 0
pH = 4.74
Hence, pH of CH3COOH is 4.74.
pH is the measure of acidity of the solution.
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