A mixture contains 0.05 moles each of CH3COONa and CH3COOH. Its pH will be (pKa of CH3COOH = 4.74)
Options
1. 4.74
2. 2.26
3. 11.26
4. 7.26
Answers
Answered by
6
★ It's a case of weak acid + it's salt with strong base.
PH = Pka + log|salt|/|acid|
=> PH = 4.72 + log (0.05/0.05)
PH = 4.72
happy to help !
Answered by
0
Answer:
PH = Pka + log|salt|/|acid|
=> PH = 4.72 + log (0.05/0.05)
PH = 4.72
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