a mixture contains 100gram each of k2co3 and mgco3 calculate the total no. of oxygen atoms
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Explanation:
Let CaCO3bexg.
Then, MgCO3is(18.4−x)g.
CaCO3→CaO+CO2
1 mol 1 mol 1 mol
100g 56g 44g
xg 10044xg
MgCO3→MgO+CO2
1 mol 1 mol 1 mol
84g 40g 44g
(18.4-x)g 8444(18.4−x)g
Total amount of CO2=10044x+8444(18.4−x) = 8.8 (given).
This gives x = 10g.
∴CaCO3=10g=0.1mol.
MgCO3=18.4−10=8.4g=0.1mol.
Total moles of CaCO3 and MgCO3=0.2mol.
∴CaCO3=50mol%.
MgCO3=50mol%.
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