A Mixture contains 105 liters of Milk and rest is waters. 15 liters of water is added to the mixture and then
20% of the mixture is taken out. In the taken-out mixture, additional amount of milk which is equal to 1/15
liters of the initial quantity of water is added such that the ratio of water to milk in the taken-out mixture
becomes 3:5. Find the initial quantity of water?
1.30
2.45
3. 60
4.75
5. none of these
Answers
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29
Answer:
Let the vessel contains 8 litres of liquid.
Let x litres of this liquid be replaced with water
when x litre of mixture is taken out it means
8
5x
litre milk and
8
3x
litre water taken out
Quantity of water in new mixture =(3−
8
3x
+x)litres
Quantity of milk in new mixture =(5−
8
5x
)litres
∴(3−
8
3x
+x)=(5−
8
5x
)
⇒5x+24=40−5x
⇒10x=16
∴x=
5
8
So, part of the mixture replaced =(
5
8
×
8
1
)=
5
1
.
Step-by-step explanation:
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