Question

A mixture contains 3.2 g methanol (molecular mass = 32u) and 4.6g ethanol. (molecular mass = 46u).Find the mole fraction of each component.​

Answer 1

your answer bro:

No. of moles of methanol = 3.2/32 = 0.1

No. of moles of ethanol = 4.6/4 = 0.1

Mole fraction of methanol = $\frac{No.\:\:of\:\:moles\:\:of\:\:methanol}{No. \:\:of\:\:moles\:\:of\:\:methanol+No. \:\:of\:\: moles\:\:of \:\:ethanol}$

Mole fraction of methanol = $\frac{0.1}{0.1+0.1}$ = 0.5

Mole fraction of ethanol = $\frac{No.\:\:of\:\:moles\:\:of\:\:ethanol}{No. \:\:of\:\:moles\:\:of\:\:methanol+No. \:\:of\:\: moles\:\:of \:\:ethanol}$

Mole fraction of ethanol = $\frac{0.1}{0.1+0.1}$ = 0.5

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