Question

A mixture contains 3.2g methanol ( molecular mass = 32u) and 4.6g ethanol ( molecular mass = 46u). Find the mole fraction of each

Answer 1

HERE IS YOUR ANSWER.
MARK BRAINLIEST PLEASE.....

Answer 2

Mole fractions of methanol and ethanol are  $0.5$ each.

Explanation:

Mole Fraction :

• Mole fraction is the ratio of the number of moles of one component of a solution.
• Or It can be the total number of moles present in the solution.

• The formula for mole fraction of  a solution containing a single or more solutes is: "Mole fraction of each solute = Number of moles of that solute divided by the total number of moles of all solutes and the solvent".

Given  - A mixture contains :

mass of methanol $=3.2g$

mass of ethanol$= 4.6 g$

We know that -

• The molar mass of methanol is $32gm ( 32u)$
• The molar mass of ethanol is $46gm (46u)$

Now calculating the number of moles in each solution,

• Number of moles in methanol $=3.2/32=0.1$
• Number of moles in methanol $=4.6/46=0.1$

Substituting the number of moles in the formula we get the mole fraction equal to -

• Mole fraction of methanol$=0.1/0.1+0.1 =0.1/0.2 =0.5$
• Mole fraction of ethyl alcohol $= 1-0.5=0.5$

Mole fraction of each methanol and ethanol is 0.5