Question

A mixture contains 3 components A, B and C in the ratio 3:4:5. If difference of the amount of B and C is 19 Kg,
then total mass of the mixture is

Answer 1

Let amount of:

A = 3x

B = 4x

C = 5x

We are given, 5x - 4x = 19

                so, x = 19

Hence, total amount of mixture = 3x + 4x + 5x = 12x = 12*19 = 228 kg