Question

A mixture contains 32g of oxygen, 28g of nitrogen and 16g of methane. Total pressure of the mixture is 60 mm. What is the partial pressure (mm) of nitrogen in mm?​

Answer 1

Answer:

As no of moles of O2=16/32=0.5 moles

no of moles of N2=28/28=1 moles

no of moles of CH4=8/16=0.5 moles

Total pressure=740mm

Partial pressure=total pressure× mole fraction of N2

Mole fraction of N2 = No of moles of N2 /total no of moles

=1/0.5+0.5+1=1/2

then partial pressure =1/2×740

                                    =370 mm

By Akshat Nashine

Answer 2

Answer:

your answer is 370mm

Explanation:

hope it will help you❤