A mixture contains 32g of oxygen, 28g of nitrogen and 16g of methane. Total pressure of the mixture is 60 mm. What is the partial pressure (mm) of nitrogen in mm?
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Answer:
As no of moles of O2=16/32=0.5 moles
no of moles of N2=28/28=1 moles
no of moles of CH4=8/16=0.5 moles
Total pressure=740mm
Partial pressure=total pressure× mole fraction of N2
Mole fraction of N2 = No of moles of N2 /total no of moles
=1/0.5+0.5+1=1/2
then partial pressure =1/2×740
=370 mm
By Akshat Nashine
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Answer:
your answer is 370mm
Explanation:
hope it will help you❤
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