Question

A mixture contains 480 litres of milk and a
certain quantity of water. 40% of the mixture
is taken out in vessel 'P' and 48 litres of water
is added to vessel 'P'. In the remaining mixture,
120 litres of milk and 72 litres of water is added.
These two mixtures are again mixed together
such that the ratio of milk to water in the
resultant mixture becomes 2:3. Find the initial
quantity of water in the mixture.​

Answer 1

Answer:

Suppose a container contains xx units of a liquid from which yy units are taken out and replaced by water. After nn operations, quantity of pure liquid

=x(1−yx)n=x(1−yx)n units.

milk contained by the container now

=40(1−440)3=40(1−110)3=40×910×910×910=4×9×9×9100=29.16