Question

A mixture contains 80% of unknown gas and 20% of oxygen. When 100cc of pure oxygen was diffused through a porous membrane, 84.51cc of the gas mixture was diffused through the same membrane, at the same time under identical conditions. Find the molecular mass of the unknown gas.

Answer 1

The rate of diffusion is the ratio of quantity diffused to time.

The rate of diffusion is inversely proportional to square root of molecular mass. When same quantity of two gases diffuses,

t

O2

t

mixture

=

M

O2

M

mixture

224

234

=

32

M

mixture

1.0446=

32

M

mixture

1.091=

32

M

mixture

M

mixture

=34.9 g/mol

Answer 2

Answer:

The rate of diffusion is the ratio of quantity diffused to time.

The rate of diffusion is inversely proportional to square root of molecular mass. When same quantity of two gases diffuses,

t ,O2t

mimixture =

M O2M mixture

224

= 32M mixture

1.0446= 32M mixmixture

1.091= 32M mixture

=34.9 g/mol

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